From f4c91ff36cb7fdc34abed391a1ce6dfb0103c182 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E6=A1=82=E5=8D=A0=E5=85=88?= <1969479820@qq.com>
Date: Tue, 8 Dec 2020 15:04:43 +0800
Subject: [PATCH] update homework_01_python/README.md.

---
 homework_01_python/README.md | 63 ++++++++++++++++++++++++++++++++++++
 1 file changed, 63 insertions(+)

diff --git a/homework_01_python/README.md b/homework_01_python/README.md
index ff6e0f1..aa5cff1 100644
--- a/homework_01_python/README.md
+++ b/homework_01_python/README.md
@@ -9,6 +9,20 @@
 ```
 One is always on a strange road, watching strange scenery and listening to strange music. Then one day, you will find that the things you try hard to forget are already gone. 
 ```
+程序如下：
+import string
+
+path = r'C:\Users\桂尔哈提\PycharmProjects\pythonProject1\en.txt'
+with open(path, 'r') as text:
+    words = [raw_word.strip(string.punctuation).lower() for raw_word in text.read().split()]  # 把所有的文字分割，忽略大小写，忽略前后的标点符号
+    words_index = set(words)
+    counts_dict = {index: words.count(index) for index in words_index}                        # 通过index写入字典
+
+    for word in sorted(counts_dict, key=lambda x: counts_dict[x], reverse=True):              # 通过字典进行字数统计
+        print('{}-{} times'.format(word, counts_dict[word]))
+
+
+
 
 **深入思考：**
 * 写完程序之后反思一下，如果单词之间是两个空格，或者是`\t`的情况下程序会不会有问题？
@@ -17,6 +31,13 @@ One is always on a strange road, watching strange scenery and listening to stran
 ### （2）组合
 有 1、2、3、4 个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？
 
+程序如下：
+for i in range(1,5):
+    for j in range(1,5):
+        for k in range(1,5):
+            if( i != k ) and (i != j) and (j != k):
+                print(i,j,k)
+
 **深入思考：**
 * 算法复杂度是？
 
@@ -30,6 +51,30 @@ One is always on a strange road, watching strange scenery and listening to stran
 * 高于 100 万元时， 超过 100 万元的部分按 1%提成， 
 从键盘输入当月利润 I，求应发放奖金总数？
 
+程序如下：
+profit = float(input("请输入当月利润，单位为元："))
+bonus = 0  # 奖金
+if profit <= 100000:
+    bonus = 10 * 0.1
+elif 100000 < profit <= 200000:
+    bonus = 100000 * 0.1 + (profit - 100000) * 0.075
+elif 200000 < profit <= 400000:
+    bonus = round(100000 * 0.1 + 100000 * 0.075 +
+                  (profit - 200000) * 0.05)
+elif 400000 < profit <= 600000:
+    bonus = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + \
+            (profit - 400000) * 0.03
+elif 600000 < profit <= 1000000:
+    bonus = 100000 * 0.1 + 100000 * 0.075 + 200000 * 0.05 + \
+            200000 * 0.03 + (profit - 600000) * 0.015
+elif profit > 1000000:
+    bonus = 100000 * 0.1 + 100000 * 0.075 + \
+            200000 * 0.05 + 200000 * 0.03 + \
+            400000 * 0.015 + (profit - 1000000) * 0.015
+else:
+    pass
+print('当月应发放奖金总数为%s元' % bonus)
+
 **深入思考：**
 * 除了用`if`手写，能否用其他方式（例如用list，然后自动实现所有的判断）来实现？
 
@@ -37,11 +82,29 @@ One is always on a strange road, watching strange scenery and listening to stran
 ### （4）循环
 输出9x9的乘法口诀表
 
+程序如下：
+
+a=[1,2,3,4,5,6,7,8,9]
+for i in range(len(a)):#控制行数
+    for j in range(i+1):#因为i是从0开始的，所以需要加一
+        print("%d*%d="%(a[j],a[i]),a[j]*a[i],end="| ")
+    print(" ")#换行
+
 **深入思考：**
 * 如何对齐，看着更清楚？
 
 ### （5）使用while循环实现输出2-3+4-5+6.....+100的和
 
+程序如下：
+i,su = 2,0
+while i <= 100:
+    if i % 2 == 0:
+        su = su + i
+    else:
+        su = su - i
+    i += 1
+print(su)
+
 **深入思考：**
 * 除了直接的方法，能否用一句话写完？
 
-- 
Gitee